Today I have got to share a very interesting topic i.e. Square Root in which most of the students or the beginners found difficulties and bit confusion also,
so I've thought to explain this
so, firstly I want to figure out where the learners found difficulties or what are the key areas where we should keep a keen eye for right solutions.
for same variable:-
so I've thought to explain this
Behaviour of square roots algebraic Terms
But later on I've extended this topic towards algebraic terms also, now our topic of discussion today is
How Square Roots behaves:-
so, firstly I want to figure out where the learners found difficulties or what are the key areas where we should keep a keen eye for right solutions.
If I talk about square roots then their behaviour as similar as algebraic Terms behaves i.e.
for same variable:-
x + x = 2x √2 + √2 = 2√2
x - x = 0 √2 - √2 = 0
x × x = x² ( √2 )² = 2
x ÷ x = 1 √2 ÷ √2 = 1
for different variable:-
x+ y = x + y √2 + √3 = √2 + √3
x - y = x - y √2 - √3 = √2 - √3
[can be solved further by evaluating square roots]
x × y = xy √2 × √3 = √ 2×3 = √6
x ÷ y = x/y √2÷ √3 = √2 / √3
So, I hope you all have cleared your doubted regarding solutions of Square Root.
√2 + ³√2
but to some extent this can be solved like
√2 × ³√2 = (2) raise to the power 5/6
but it will have no impact in subject to solution.
for exponents solutions refer to our post exponents and their rules
x - x = 0 √2 - √2 = 0
x × x = x² ( √2 )² = 2
x ÷ x = 1 √2 ÷ √2 = 1
for different variable:-
x+ y = x + y √2 + √3 = √2 + √3
x - y = x - y √2 - √3 = √2 - √3
[can be solved further by evaluating square roots]
x × y = xy √2 × √3 = √ 2×3 = √6
x ÷ y = x/y √2÷ √3 = √2 / √3
So, I hope you all have cleared your doubted regarding solutions of Square Root.
Q. but what if square roots and cube roots given
Ans. they will remain unsolved√2 + ³√2
but to some extent this can be solved like
√2 × ³√2 = (2) raise to the power 5/6
but it will have no impact in subject to solution.
for exponents solutions refer to our post exponents and their rules
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