Importance of Barckets in math

Hello everyone..!!!

Hope you're doing well.
Our today's topic is

Brackets :How to use in equation solution

Here I'm going to explain

• what If one don't place brackets at right positions while solving any equation consisting one or more Functions?

• what changes comes for not placing brackets?

• what happens if brackets placed at right place?

So without wasting time I'm starting,

suppose an equation is given

5x+ 4x =9x

but

5x+ -4x =9x,-9x , 1x, -1x

this creates confusion to some learners that from which function the equation will be operated,
so this should be
5x+(-4x) = 5x -4x = 1x or x

similarly,

22+ 6 -8 ×-7 .....?????
this should be written correctly first i.e.
22 + 6 - 8 × (-7)
apply Bodmas rule

22 + 6 - -56
again it should be written correctly

22 + 6 - (-56)

22 + 6 + 56

84.

and in algebra if the equation​ is,

3y + 5 × -x - 6÷ -3 ...😒😓

quite confusion ha...!!!
OK, see below,

3y + 5× (-x) -6 ÷(-3)

3y -5x + 6/3

ans .
3y - 5x + 2.

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again if

Q. Divide 6x + -4x - 3y by 3.

if we write the above statement like

     6x +(-4x) -3y ÷3

then it is totally wrong as instead of the equation only last term i.e. -3y is seems to be divided by 3,
so, we should place suitable Brackets

like

    [ 6x +(-4x) -3y ] / 3

now this is explaining itself that the whole equation is divided by 3.

    [ 6x -4x -3y] /3

    [ 2x -3y ] /3

this is it.
I hope this tutorial of importance of brackets in math, remain helpful for you.
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